73=33x^2

Solution for 73=33x^2 equation:

73=33x^2

We move all terms to the left:

73-(33x^2)=0

a = -33; b = 0; c = +73;
Δ = b2-4ac
Δ = 02-4·(-33)·73
Δ = 9636
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9636}=\sqrt{4*2409}=\sqrt{4}*\sqrt{2409}=2\sqrt{2409}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{2409}}{2*-33}=\frac{0-2\sqrt{2409}}{-66}
=-\frac{2\sqrt{2409}}{-66}
=-\frac{\sqrt{2409}}{-33}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{2409}}{2*-33}=\frac{0+2\sqrt{2409}}{-66}
=\frac{2\sqrt{2409}}{-66}
=\frac{\sqrt{2409}}{-33}
$